## Chemistry: The Molecular Science (5th Edition)

$KOH$ is the limiting reactant.
1. For 1 mol of that reaction to occur, calculate the necessary mass: - Multiply the molar mass and the balance coefficient: $KOH$: 39.1* 1 + 16* 1 + 1.008* 1 = 56.108g/mol * 4 mol= 224.432g $MnO_2$: 54.94* 1 + 16* 2 = 86.94g/mol * 2 mol = 173.88g $O_2$: 16* 2 = 32g/mol * 1 mol = 32g $Cl_2$: 35.45 * 2 = 70.90g/mol * 1 mol = 70.90g $KOH$ needs a greater mass, so, it is the limiting reactant.