Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 2 - Chemical Compounds - Questions for Review and Thought - Applying Concepts - Page 90f: 123i


$6.022 \times 10^{23}$ atoms $Ca$ has the greater number of atoms.

Work Step by Step

- 1 g calcium: Molar mass ($Ca$) = 40.1 g/mol Therefore: $1g \times \frac{1 mol}{40.1g} \approx 0.025$ $moles$ - $6.022 \times 10^{23}$ atoms of $Ca$ $6.022 \times 10^{23}$ atoms = 1 mol Therefore: $6.022 \times 10^{23}$ $Ca$ = 1 mol $(Ca)$ - Since we are comparing the same kind of specie $(Ca)$ we can assume that: Since 1 mol > 0.025 moles, the number of atoms is greater in $6.022 \times 10^{23}$ atoms ($Ca$).
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