Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 2 - Chemical Compounds - Questions for Review and Thought - Applying Concepts - Page 90f: 124b

Answer

$6.022 \times 10^{24}$ atoms of lead has the greater mass.

Work Step by Step

- $6.022 \times 10^{24}$ lead atoms: $6.022 \times 10^{24} \times \frac{1 mol}{6.022 \times 10^{23}} = 10$ $moles$. Since we are comparing the masses of 2 quantities of the same type of atom ($Pb$), the one with the higher number of moles has the greater mass. 10 moles $(Pb)$ > 1 mol $(Pb)$ Thus, $6.022 \times 10^{24}$ atoms of lead has the greater mass.
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