Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 2 - Chemical Compounds - Questions for Review and Thought - Applying Concepts - Page 90f: 124b


$6.022 \times 10^{24}$ atoms of lead has the greater mass.

Work Step by Step

- $6.022 \times 10^{24}$ lead atoms: $6.022 \times 10^{24} \times \frac{1 mol}{6.022 \times 10^{23}} = 10$ $moles$. Since we are comparing the masses of 2 quantities of the same type of atom ($Pb$), the one with the higher number of moles has the greater mass. 10 moles $(Pb)$ > 1 mol $(Pb)$ Thus, $6.022 \times 10^{24}$ atoms of lead has the greater mass.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.