Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 2 - Chemical Compounds - Questions for Review and Thought - Applying Concepts - Page 90f: 123g


$9.6\ g$ $Li$ has the greater number of atoms.

Work Step by Step

- $107.9g$ $Ag$: Molar mass ($Ag$) = 107.9 g/mol. Therefore, 107.9g $Ag$ = 1 mol $Ag$ - 9.6g $Li$ Molar mass ($Li$) = 6.9g/mol $9.6g \times \frac{1 mol}{6.9g} \approx 1.39$ $moles$. Thus, using the given information, it follows: $1.39$ $moles$ $Li$ > $1$ $mol$ $Ag$
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