Answer
$9.6\ g$ $Li$ has the greater number of atoms.
Work Step by Step
- $107.9g$ $Ag$:
Molar mass ($Ag$) = 107.9 g/mol.
Therefore, 107.9g $Ag$ = 1 mol $Ag$
- 9.6g $Li$
Molar mass ($Li$) = 6.9g/mol
$9.6g \times \frac{1 mol}{6.9g} \approx 1.39$ $moles$.
Thus, using the given information, it follows:
$1.39$ $moles$ $Li$ > $1$ $mol$ $Ag$
