Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 2 - Chemical Compounds - Questions for Review and Thought - Applying Concepts - Page 90f: 123j


1g Chlorine atoms and 1g Chlorine molecules have the same amount of atoms.

Work Step by Step

- 1g chlorine atoms $(Cl)$: Molar mass: 35.5g/mol So: $1g \times \frac{1 mol}{35.5g} = 0.0282$ moles of chlorine atoms. Which means: 0.0282 moles of atoms. - 1g chlorine molecules $(Cl_2)$: Molar mass: 71 g/mol So: $1g \times \frac{1mol}{71g} = 0.0141$ moles of chlorine molecules. - But, each chlorine molecule $(Cl_2)$ has 2 atoms, so: $n°(atoms) = 0.0141$ $moles$ $ * 2 = 0.0282$ $moles$. Therefore, they both have the same number of atoms.
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