Answer
$^{22}_{11}Na → ^{0}_{-1}e + ^{22}_{12}Mg$
Work Step by Step
Na-22 undergoes beta decay to form Mg-22. Thus, we find:
$^{22}_{11}Na → ^{0}_{-1}e + ^{22}_{12}Mg$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.