Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 18 - Nuclear Chemistry - Problem Solving Practice 18.2 - Page 789: d


$^{22}_{11}Na → ^{0}_{-1}e + ^{22}_{12}Mg$

Work Step by Step

Na-22 undergoes beta decay to form Mg-22. Thus, we find: $^{22}_{11}Na → ^{0}_{-1}e + ^{22}_{12}Mg$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.