Answer
$^{11}_{6}C → ^{11}_{5}B + ^{0}_{1}e $
Work Step by Step
C-11 undergoes positron emission to form B-11. Thus, we find:
$^{11}_{6}C → ^{11}_{5}B + ^{0}_{1}e $
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 18 - Nuclear Chemistry - Problem Solving Practice 18.2 - Page 789: a
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