## Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning

# Chapter 18 - Nuclear Chemistry - Problem Solving Practice 18.2 - Page 789: b

#### Answer

$^{35}_{16}S → ^{35}_{17}Cl + ^{0}_{-1}e$

#### Work Step by Step

S-35 undergoes beta decay to form Cl-35. Thus, we find: $^{35}_{16}S → ^{35}_{17}Cl + ^{0}_{-1}e$

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