Answer
$^{26}_{13}Al + ^{0}_{-1}e→ ^{26}_{12}Mg$
Work Step by Step
Positron emission:
$^{26}_{13}Al → ^{0}_{+1}e + ^{26}_{12}Mg$
Electron Capture:
$^{26}_{13}Al + ^{0}_{-1}e→ ^{26}_{12}Mg$
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 18 - Nuclear Chemistry - Exercise 18.2 - Nuclear Reactions - Page 789: a
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