## Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning

# Chapter 12 - Chemical Equilibrium - Questions for Review and Thought - Topical Questions - Page 563a: 15b

#### Answer

$k =\frac{[NO_4]^4[H_2O]^6}{[NH_3]^4[O_2]^5}$

#### Work Step by Step

Recall, in the expression for the equilibrium constant, the concentrations of the reactants are in the numerator, and each is raised to an exponent that is the same as the coefficient in front of each reactant, and then these values are multiplied by each other. The same thing happens with the products, which are in the denominator. Recall, solids are not included in the expression for the equilibrium constant. Keeping this in mind, we obtain: $k =\frac{[NO_4]^4[H_2O]^6}{[NH_3]^4[O_2]^5}$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.