Answer
58.9 mL
Work Step by Step
$V_{1}$ = 48.3 mL
$T_{1}$ = (22+273)K = 295 K
$T_{2}$ = (87+273)K = 360 K
According to Charles' law, $\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$
Or $V_{2} = \frac{V_{1}T_{2}}{T_{1}}$ = $\frac{48.3mL\times360K}{295K}$ = 58.9 mL
