## Chemistry: Molecular Approach (4th Edition)

$V_{1}$ = 48.3 mL $T_{1}$ = (22+273)K = 295 K $T_{2}$ = (87+273)K = 360 K According to Charles' law, $\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$ Or $V_{2} = \frac{V_{1}T_{2}}{T_{1}}$ = $\frac{48.3mL\times360K}{295K}$ = 58.9 mL