Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 5 - Exercises - Page 240: 28


a. $$ 653.2 \space torr$$ b.$$ 0.8586 \space atm$$ c.$$ 25.69 \space in Hg$$ d.$$ 12.6 \space psi$$

Work Step by Step

a. $$ 652.5 \space mmHg \times \frac{1 \space torr}{1 \space mmHg}= 653.2 \space torr$$ b.$$ 652.5 \space mmHg \times \frac{1 \space atm}{760 \space mmHg}= 0.8586 \space atm$$ c.$$ 652.5 \space mmHg \times \frac{1 \space atm}{760 \space mmHg}\times \frac{29.92 \space in Hg}{1 \space atm} = 25.69 \space in Hg$$ d.$$ 652.5 \space mmHg \times \frac{1 \space atm}{760 \space mmHg}\times \frac{14.7 \space psi}{1 \space atm} = 12.6 \space psi$$
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