## Chemistry: Molecular Approach (4th Edition)

We have,$P_{1} V_{1} = P_{2} V_{2}$ (combined gas equation) We are required to find: $P_{2}$ (final pressure) Therefore, (13.9) (1.22) = (10.3) $P_{2}$ $P_{2}$ = $\frac{(13.9)(1.22)}{(10.3)}$ $P_{2}$ = 1.65 atm