Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 5 - Exercises - Page 240: 32


1.65 atm

Work Step by Step

We have,$ P_{1} V_{1} = P_{2} V_{2} $ (combined gas equation) We are required to find: $P_{2}$ (final pressure) Therefore, (13.9) (1.22) = (10.3) $P_{2}$ $P_{2}$ = $\frac{(13.9)(1.22)}{(10.3)}$ $P_{2}$ = 1.65 atm
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