## Chemistry: Molecular Approach (4th Edition)

Published by Pearson

# Chapter 16 - Self-Assessment Quiz - Page 767: Q5

(d) 0.018 M

#### Work Step by Step

1. Calculate the hydronium ion concentration: $$[H_3O^+] = 10^{-pH} = 10^{-1.75} = 1.8 \times 10^{-2} \space M$$ 2. Since $HNO_3$ is a strong acid: $$[HNO_3] = [H_3O^+] = 1.8 \times 10^{-2} \space M = 0.018 \space M$$

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