## Chemistry: Molecular Approach (4th Edition)

Published by Pearson

# Chapter 16 - Self-Assessment Quiz - Page 767: Q4

#### Answer

(b) $5.3 \times 10^{-6} \space M$

#### Work Step by Step

We find: $$[OH^-] = \frac{1.0 \times 10^{-14}}{[H_3O^+]} = \frac{1.0 \times 10^{-14}}{ 1.9 \times 10^{-9} } = 5.3 \times 10^{-6} \space M$$

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