Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 16 - Self-Assessment Quiz - Page 767: Q1


(d) $ClO{_2}^-$ is the conjugate base in this reaction.

Work Step by Step

1. Identify the acid. $HClO_2$ is donating a proton to $H_2O$; therefore, it is the acid of this reaction. 2. The conjugate base is what the acid becomes after losing a proton. $HClO_2$ without a proton is $Cl{O_2}^-$. Thus, this anion is the conjugate base of the reaction.
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