## Chemistry: Molecular Approach (4th Edition)

(d) $ClO{_2}^-$ is the conjugate base in this reaction.
1. Identify the acid. $HClO_2$ is donating a proton to $H_2O$; therefore, it is the acid of this reaction. 2. The conjugate base is what the acid becomes after losing a proton. $HClO_2$ without a proton is $Cl{O_2}^-$. Thus, this anion is the conjugate base of the reaction.