## Chemistry: Molecular Approach (4th Edition)

We know that $V=\frac{density}{mass}$ We plug in the known values to obtain: $V=\frac{1.1kg}{2700\frac{Kg}{m^3}}=4.074\times 10^{-4}m^3$ Now $l=\frac{V}{a\times b}$ $l=\frac{4.074\times 10^{-4}}{0.304\times 1.6\times 10^{-5}}=83.76m$