## Chemistry: Molecular Approach (4th Edition)

Published by Pearson

# Chapter 1 - Exercises - Page 41: 128

#### Answer

$\underline{23.2\text{ miles/h}}$ and $\underline{22.3\text{ miles/h}}$

#### Work Step by Step

$1\text{ mile}=1600\text{ m}$ and $100\text{ yard}=91.4\text{ m}\,\,\,\left[ \because \,\,1.094\,yard=1\,m \right]$ So, for 100-meter dash, the speed is calculated as follows: $\left( \frac{100\text{ m}}{9.69\text{ s}} \right)\left( \frac{3600\text{ s}}{1\text{ h}} \right)\left( \frac{1\text{ mile}}{1600\text{ m}} \right)=23.2\text{ miles/h}$ Similarly, for 100-yard dash, the speed is calculated as follows: $\left( \frac{100\text{ yard}}{9.21\text{ s}} \right)\left( \frac{\text{91}\text{.4 m}}{100\text{ yard}} \right)\left( \frac{1\text{ mile}}{1600\text{ m}} \right)\left( \frac{3600\text{ s}}{1\text{ h}} \right)=22.3\text{ miles/h}$

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