Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 1 - Exercises - Page 41: 128


\[\underline{23.2\text{ miles/h}}\] and \[\underline{22.3\text{ miles/h}}\]

Work Step by Step

\[1\text{ mile}=1600\text{ m}\] and \[100\text{ yard}=91.4\text{ m}\,\,\,\left[ \because \,\,1.094\,yard=1\,m \right]\] So, for 100-meter dash, the speed is calculated as follows: \[\left( \frac{100\text{ m}}{9.69\text{ s}} \right)\left( \frac{3600\text{ s}}{1\text{ h}} \right)\left( \frac{1\text{ mile}}{1600\text{ m}} \right)=23.2\text{ miles/h}\] Similarly, for 100-yard dash, the speed is calculated as follows: \[\left( \frac{100\text{ yard}}{9.21\text{ s}} \right)\left( \frac{\text{91}\text{.4 m}}{100\text{ yard}} \right)\left( \frac{1\text{ mile}}{1600\text{ m}} \right)\left( \frac{3600\text{ s}}{1\text{ h}} \right)=22.3\text{ miles/h}\]
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