Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 1 - Exercises - Page 41: 124


\[\underline{\text{5}\text{.94 km}}\]

Work Step by Step

Volume of gasoline in the tank of soda can is equal to \[355\text{ mL}\]. \[1\text{ mL}=0.00026\text{ gal}\] Thus, volume in gallons is written as follows: \[\begin{align} & \text{Volume}=355\times 0.00026\text{ gal} \\ & =0.\text{09 gal} \end{align}\] Thus: \[\begin{align} & \text{distance}=\left( 41\times 0.09 \right)\text{ miles} \\ & =3.69\text{ miles} \end{align}\] Now, \[\text{1 mile}=1.61\text{ km}\] Thus, distance traveled in kilometers is as follows: \[\begin{align} & \text{distance}=\left( 3.69\times \text{1}\text{.61} \right)\text{ km} \\ & =5.94\text{ km} \end{align}\]
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