Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179i: 115


$76.2\ m^3$

Work Step by Step

Number of moles of the dye: $1.0\ g \div 319.85\ g/mol=3.126\ mmol$ From the concentration: $3.126\times10^{-3}\ mol\div 4.1\times 10^{-8}\ M=76.2\times10^{3}\ L= 76.2\ m^3$
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