## Chemistry and Chemical Reactivity (9th Edition)

$3.13$
Concentration of the acid: $[H_3O^+]=10^{-1.92}=0.012\ M$ Number of moles of hydronium remaining after the neutralization: $0.25\ L\times 0.012\ M-0.0105\ M\times 0.250\ L=0.375\ mmol$ Concentration: $0.375\ mmol/500\ mL=0.75\ mM$ pH: $-log(0.00075)=3.13$