Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179i: 110


$0.0289\ g$

Work Step by Step

Number of moles of acid: $0.125\ L\times10^{-2.56}\ M=0.000344\ mol$ From stoichiometry, same as bicarbonate: Mass: $0.000344\ mol\times 84.01\ g/mol=0.0289\ g$
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