Answer
$0.0289\ g$
Work Step by Step
Number of moles of acid:
$0.125\ L\times10^{-2.56}\ M=0.000344\ mol$
From stoichiometry, same as bicarbonate:
Mass:
$0.000344\ mol\times 84.01\ g/mol=0.0289\ g$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179i: 110
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