Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179i: 107


See the answer below.

Work Step by Step

Number of moles of $I_2$: $0.246\ M\times 40.21\ mL/1000 \ mL/L=0.00989\ mol$ From stoichiometry: $0.00989\ mol\times 2/1=0.01978\ mol$ thiosulfate. Mass of sodium thiosulfate: $0.01978\ mmol\times 158.10\ g/mol=3.127\ g$ Mass percentage: $3.127/3.232\times 100\%=96.76\%$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.