## Chemistry and Chemical Reactivity (9th Edition)

a) Reacted concentration: x $K=[dim]/[mon]^2$ $3.2\times10^4=x^2/(5.4\times10^{-4}-2x)$ $x^2+6.4\times10^4x-17.28=0$ $x=2.70\times10^{-4}\ M$ $f=(1-2x/5.4\times10^{-4})\times100\%\approx100\%$ b) Since the reaction is exothermic, as the temperature increases the equilibrium shifts towards the monomer.