Answer
$K_p=0.215$
Work Step by Step
$K_p=p(NH_3)\times p(HI)$
Gases weren't present at the beginning:
$p(NH_3)=p(HI)=p/2$
$K_p=(0.464\ atm)^2$
$K_p=0.215$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 15 Principles of Chemical Reactivity: Equilibria - Study Questions - Page 583e: 45
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