Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 15 Principles of Chemical Reactivity: Equilibria - Study Questions - Page 583e: 54


$0.089\ mol$

Work Step by Step

a) $K_p=p(CO)^3p(CO_2)^3$ $p(CO)=p(CO_2)=p/2$ $K_p=(p/2)^3(p/2)^3$ $K_p=p^6/64$ $K_p=10^{-6}$ b) $K_p=p(CO)^6\rightarrow p(CO)=0.1\ atm=p(CO_2)$ $p(CO)=n_{CO}RT/V$ $n_{CO}=0.033\ mol$ $n_{Reacted}=0.01\ mol$ $n_{Unreacted}=0.100\ mol-0.01\ mol=0.089\ mol$
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