Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 15 Principles of Chemical Reactivity: Equilibria - Study Questions - Page 583e: 51


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Work Step by Step

a) Reacted concentration: x $K_c=[NH_3][H_2S]$ $1.8\times10^{-4}=x^2$ $x=0.0134\ M$ $[NH_3]=[H_2S]=0.0134\ M$ b) Reacted concentration: x $K_c=[NH_3][H_2S]$ $1.8\times10^{-4}=(0.02+x)x$ $x=0.0067\ M$ $[NH_3]=0.0267\ M, [H_2S]=0.0067\ M$
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