# Chapter 15 Principles of Chemical Reactivity: Equilibria - Study Questions - Page 583e: 51

#### Work Step by Step

a) Reacted concentration: x $K_c=[NH_3][H_2S]$ $1.8\times10^{-4}=x^2$ $x=0.0134\ M$ $[NH_3]=[H_2S]=0.0134\ M$ b) Reacted concentration: x $K_c=[NH_3][H_2S]$ $1.8\times10^{-4}=(0.02+x)x$ $x=0.0067\ M$ $[NH_3]=0.0267\ M, [H_2S]=0.0067\ M$

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