Answer
$ C=0.0027\ mol/L$
Work Step by Step
For a second-order reaction:
$1/C-1/C_0=kt$
$1/C-1/0.015=30\times 10\rightarrow C=0.0027\ mol/L$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 14 Chemical Kinetics: The Rates of Chemical Reactions - Study Questions - Page 553b: 24
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