Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 14 Chemical Kinetics: The Rates of Chemical Reactions - Study Questions - Page 553b: 28


$t=2.45\ h$

Work Step by Step

For a first-order reaction; $ln(C/C_0)=-k.t; k=0.693/t_{1/2}$ Assuming constant volume, we can use this equation on a mass basis. $ln(0.25\ mg\div 7.50\ mg)=-0.693/30\ min\times t$ $t=147.2\ min=2.45\ h$
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