Answer
$t=2.45\ h$
Work Step by Step
For a first-order reaction;
$ln(C/C_0)=-k.t; k=0.693/t_{1/2}$
Assuming constant volume, we can use this equation on a mass basis.
$ln(0.25\ mg\div 7.50\ mg)=-0.693/30\ min\times t$
$t=147.2\ min=2.45\ h$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 14 Chemical Kinetics: The Rates of Chemical Reactions - Study Questions - Page 553b: 28
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