Answer
$k=0.0056\ min^{-1}$
Work Step by Step
First oder process: $ln([N_2O_5]/[N_2O_5]_0)=-kt$
Assuming same solution volume, we can use this equation in a mass basis:
$ln(2.50/2.56)=-k\times 4.26\ min\rightarrow k=0.0056\ min^{-1}$
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