## Chemistry and Chemical Reactivity (9th Edition)

For a first-order reaction: $ln(C/C_0)=-kt$ Assuming constant volume, we can use this equation on a mass basis. $ln(m/2.00\ g)=-0.0216\ min^{-1}\times 3\ min\rightarrow m=1.87\ g$ Consumed moles: $(2.00-1.87)\ g\div58.08\ g/mol=0.0022\ mol$ Formed N2 mass: $0.0022\ mol\times 28.01\ g/mol=0.060\ g$