Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 13 Solutions and Their Behavior - Study Questions - Page 505c: 61


$0.592\ g$

Work Step by Step

The number of moles of ions: $0.100\ m\times 0.125\ kg=0.0125\ mol$ The number of moles of Na2SO4: $0.0125\ mol\div 3=0.0042\ mol$ Mass of Na2SO4: $0.0042\ mol\times 142.04\ g/mol=0.592\ g$
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