Answer
See the answer below.
Work Step by Step
In 1 liter of solution:
Number of moles of solute: $14.8\ mol/L\times 1\ L=14.8\ mol$
Mass of solute: $14.8\ mol\times 17.03\ g/mol=252.04\ g$
Mass of solution: $1000\ cm^3\times 0.90\ g/cm^3=900\ g$
Mass of solvent: $900-252.4=647.96\ g$
Number of moles of solvent: $647.96\ g\div 18.015\ g/mol=35.97\ mol$
Molality: $14.8\ mol\div 0.648\ kg=22.84\ m$
Weight percent: $252.04/900\times100\%=28\%$
Mole fraction: $14.8\div(14.8+35.97)=0.29$
