Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 13 Solutions and Their Behavior - Study Questions - Page 505c: 52


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Work Step by Step

a) Radius: $0.5\times10^2\ nm=0.5\times10^{-5}\ cm$ Volume: $4\pi/3\times r^3=5.24\times10^{-16}\ cm^3$ Surface area: $4\pi\times r^2=3.14\times10^{-10}\ cm^2$ b) 1.0 $cm^3$ total volume: $1.0\ cm^3\div5.24\times10^{-16}\ cm^3=1.91\times10^{15}$ Surface area of this many spheres: $1.91\times10^{15}\times 3.14\times10^{-10}\ cm^2 = 6.0\times10^5\ cm^2=60\ m^2$
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