Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 13 Solutions and Their Behavior - Study Questions - Page 505c: 53


$107.5\ g/mol$

Work Step by Step

Freezing point depression: $-0.36^{\circ}C$ Molality: $\Delta T_f=K_fm\rightarrow -0.36^{\circ}C=-1.86^{\circ}C/m\times m\rightarrow m=0.194\ mol/kg$ Molar mass: $0.52\ g\div(0.194\ mol/kg\times (25/1000)kg))=107.5\ g/mol$
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