Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 10 Gases and Their Properties - Study Questions - Page 403g: 91


$17.1\ mmHg$

Work Step by Step

Since T and V are constant, $P\propto n$ $P_{N_2}= 120×4/(4+3)=68.6\ mmHg$ $P_{F_2}= 120×3/(4+3)=51.4\ mmHg$ Final pressure: $P=120\ mmHg×1/(4+3)=17.1\ mmHg$
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