Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 10 Gases and Their Properties - Study Questions - Page 403g: 85

Answer

$n=0.0128\ mol$

Work Step by Step

Total pressure: $22+755=777\ mmHg$ $PV=nRT$ $n=\frac{(777/760×1\ atm)×0.305\ L}{0.082\times 298\ K}$ $n=0.0128\ mol$
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