Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 10 Gases and Their Properties - Study Questions - Page 403g: 84

Answer

See the answer below.

Work Step by Step

From Graham's law: $0.66\ mol/4.8\ min\div 0.66\ mol/t =\sqrt{16.04/88.0}$ $t=2.05\ min$
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