Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 10 Gases and Their Properties - Study Questions - Page 403g: 83


See the answer below.

Work Step by Step

From Graham's law: $0.033\ mol/60\ s\div 0.033\ mol/104\ s=\sqrt{x/44.0}$ $x=132.2\ g/mol$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.