Answer
$0.229atm$
Work Step by Step
We can calculate the vapor pressure of water as follows:
$P_{soln}=(\frac{n_{H_2O}}{n_{H_2O}+n_{solute}})P^{\circ}_{H_2O}$
We plug in the known values to obtain:
$P_{soln}=(\frac{1000mol}{1000mol+75.649mol})(0.2467atm)$
$P_{soln}=0.229atm$
