Answer
2.4 Liters
Work Step by Step
Moles of $AgNO_3$ = $10. \text{ grams}*\frac{1 \text{ mol}}{169.87 \text{ grams}}=0.059$ moles
$0.59 \text{ moles}*\frac{1 \text{ L}}{0.25 \text{ moles}}=2.4 $ L
Chemistry 9th Edition
by Zumdahl, Steven S.; Zumdahl, Susan A.
Published by
Cengage Learning
ISBN 10:
1133611095
ISBN 13:
978-1-13361-109-7
Chapter 4 - Types of Chemical Reactions and Solution Stoichiometry - Exercises - Page 181: 34
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