Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 4 - Types of Chemical Reactions and Solution Stoichiometry - Exercises: 29

Answer

a. 1.00 M b. 2.0 M c. 0.187 M d. 0.0188 M

Work Step by Step

a. $\frac{0.100 \text{ mol}}{0.1000 \text{ L}}=1$M b. $\frac{2.5\text{ mol}}{1.25\text{ L}}=2$M c. $5.00 \text{ grams}∗\frac{1\text{ mol}}{53.491\text{ grams}}=0.0935 \text{ moles}$ $\frac{0.0935 \text{ mols}}{0.500 \text{ L}}=0.187 \text{ M}$ d. ${1.00\text{ grams}}∗\frac{1\text{ mol}}{212.27\text{ grams}}=0.00471 \text{ mol}$ $\frac{0.00471 \text{ mol}}{0.2500\text{ L}}=0.0188$ M
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.