Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 4 - Types of Chemical Reactions and Solution Stoichiometry - Exercises - Page 181: 28


5.2 M C2H5OH

Work Step by Step

75.0 mL * $\frac{0.79 g}{mL}$ * $\frac{1mol}{46.07 g}$ = 1.3 mol C2H5OH; molarity= $\frac{1.3 mol}{0.250L}$ = 5.2 M C2H5OH
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