Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 2 - Atoms, Molecules, and Ions - Section Problems - Page 74: 118


The identity of "Y" is the element: Krypton.

Work Step by Step

$6.02 \times 10^{23}$ atoms = 1 mol of atoms. If 1 mol of this element has a mass of 83.80 g, then the molar mass for this type of atom is equal to 83.80 g/mol. Since the atomic weight is numerically equal to the molar mass, this element weighs $83.80$ $u$. Using a periodic table, we can see that Krypton ("Kr") has exactly this weight.
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