Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 2 - Atoms, Molecules, and Ions - Section Problems - Page 74: 100

Answer

(a) 7 protons, 8 neutrons and 7 electrons. (b) 27 protons, 33 neutrons and 27 electrons. (c) 53 protons, 78 neutrons and 53 electrons. (d) 58 protons, 90 neutrons and 58 electrons.

Work Step by Step

("P" = Number of protons; "$e^-$ = Number of electrons"; "N" = Number of neutrons) 1. Number of protons: $P = Z$ (Atomic number) (Bottom left number); (a) 7 (b) 27 (c) 53 (d) 58 2. Number of electrons $e^- = P$ (because they are neutral) (a) 7 (b) 27 (c) 53 (d) 58 3. Number of neutrons: Each proton and neutron is responsible for 1 unit of mass: $P + N = A$ ("A" is the top left number) Therefore: $N = A - P$ (a) $N = 15 - 7 = 8$ (b) $N = 60 - 27 = 33$ (c) $N = 131 - 53 = 78$ (d) $N = 148 - 58 = 90$
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