## Chemistry (7th Edition)

The mass of $6.02 \times 10^{23}$ atoms of the element is equal to "x" g. The answer is numerically equal to the atomic weight of "x".
$6.02 \times 10^{23}$ atoms equals 1 mol of atoms of this element. The atomic weight of an element is numerically equal to the mass in grams of 1 mol of atoms of this element.