## Chemistry (7th Edition)

Published by Pearson

# Chapter 1 - Chemical Tools: Experimentation and Measurement - Section Problems - Page 29: 51

#### Answer

- There are $10^6$ $µL$ in 1 L. - There are $2.0 \times 10^4 µL$ in $20$ $mL$

#### Work Step by Step

$1$ $L \times \frac{1 µL}{10^{-6}L} = 10^{6}$ $µL$ - There are $10^6$ $µL$ in 1 L. $20$ $mL \times \frac{10^{-3}L}{1mL} \times \frac{1µL}{10^{-6}L} = 2.0 \times 10^4$ $µL$ - There are $2.0 \times 10^4 µL$ in $20$ $mL$

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