## Chemistry (7th Edition)

- There are $10^9$ $pg$ in 1 mg and $3.5 \times 10^4$ $pg$ in $35$ $ng$.
1 mg $= 10^{-3}g \times \frac{1 pg}{10^{-12}g} = 10^9pg$ - There are $10^9$ $pg$ in 1 mg. $35 ng \times \frac{10^{-9}g}{1ng} \times \frac{1pg}{10^{-12}} = 3.5 \times 10^4$ $pg$ - There are $3.5 \times 10^4$ $pg$ in $35$ $ng$.