Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 1 - Chemical Tools: Experimentation and Measurement - Section Problems - Page 29: 49

Answer

(a) $154$ $pm$ is larger. (b) $2.02\times 10^2km$ is larger. (c) $3.1 \times 10^{15}µA$ is larger.

Work Step by Step

(a) Convert all the values to "meters" 1 $pm$ = $10^{-12}$ $m$ : $154 $ $pm = 1.54 \times 10^2 \times (10^{-12}) $ $m$ $1.54 \times 10^{-10}$ $m$ 1 $cm$ = $10^{-2}$ $m$ $7.7 \times 10^{-9}$ $cm = 7.7 \times 10^{-9}$ $\times 10^{-2}$ $m$ $7.7 \times 10^{-11} $ $m$ - Now, compare the values. $1.54 \times 10^{-10}$ $m$ $> 7.7 \times 10^{-11}$ $m$ So, $154$ $pm$ is larger. (b) Convert all the measurements to "meters": $1.86 \times 10^{11}µm \times \frac{10^{-6} m}{1µm} = 1.86 \times 10^{5}m$ $2.02 \times 10^{2} km \times \frac{10^{3}m}{1 km} = 2.02 \times 10^{5}m$ - Now, compare the values. $2.02 \times 10^5m > 1.86 \times 10^5 m $ So, $2.02\times 10^2km$ is larger. (c) Convert all the measurements to "Ampere": $2.9GA \times \frac{10^9A}{1GA}= 2.9 \times 10^9A$ $3.1 \times 10^{15} µA \times \frac{10^{-6}A}{1µA} = 3.1 \times 10^9A$ - Now, compare the values. $3.1 \times 10^9A > 2.9 \times 10^9A$ So, $3.1 \times 10^{15}µA$ is larger.
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