Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 5 - Section 5.1 - Energy and Energy Changes - Checkpoint - Page 191: 5.1.5


c) i=iii$\lt$ii$\lt$iv

Work Step by Step

Electrostatic potential energy $E_{el}=k\frac{Q_{1}Q_{2}}{d}$, $k$ is a constant. For (i), $E_{el}=k\frac{(+1)(-3)}{d}=-3\times\frac{k}{d}$ For (ii), $E_{el}=k\frac{(+2)(-2)}{d}=-4\times\frac{k}{d}$ For (iii), $E_{el}=k\frac{(+2)(-3)}{2d}=-3\times\frac{k}{d}$ For (iv), $E_{el}=k\frac{(+4)(-4)}{3d}=-\frac{16}{3}\times\frac{k}{d}$ Comparing the electrostatic potential energies, we can arrange them in increasing order as: i=iii$\lt$ii$\lt$iv The correct option is (c).
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